10.149.0.0/16 Supernet
10.149.0.0/16 is a private IPv4 supernet with mask 255.255.0.0. It holds 65,534 usable hosts (10.149.0.1–10.149.255.254) and contains 256 /24 subnets.
Supernet details
| Property | Value |
|---|---|
| Network address | 10.149.0.0 |
| CIDR notation | 10.149.0.0/16 |
| Subnet mask | 255.255.0.0 |
| Wildcard mask | 0.0.255.255 |
| Usable host range | 10.149.0.1 – 10.149.255.254 |
| Broadcast address | 10.149.255.255 |
| Total addresses | 65,536 |
| Usable hosts | 65,534 |
| Contained /24 subnets | 256 |
How it splits into /24s
A /16 keeps 16 network bits and 16 host bits. It is most often divided into 256 /24 networks — 10.149.0.0/24, 10.149.1.0/24, … 10.149.255.0/24 — one per value of the third octet.
This block is part of the private range 10.0.0.0/8 (RFC 1918), reserved for internal networks.
Split it your way
Use our subnet calculator to divide this /16 into any prefix from /17 to /30.
Frequently asked questions
What is the subnet mask for 10.149.0.0/16?
A /16 uses mask 255.255.0.0 (wildcard 0.0.255.255), giving 65,536 total addresses and 65,534 usable hosts.
How many /24 subnets are in 10.149.0.0/16?
256 — one for each value of the third octet, from 10.149.0.0/24 to 10.149.255.0/24.
How many hosts does a /16 support?
65,534 usable hosts (65,536 total minus the network and broadcast addresses).
Related
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